Trigonometry and angles of ascent and descent in aviation

2 ANSWERS

1. Angelina
   

    An air traffic manager should assess the bend of fall (the bend of depression) for an incoming jet. The jet's crew accounts that their land expanse is 46km from the groundwork of the command tower and that the plane is soaring at an altitude of 5.8km. Find the assess of the bend of fall to the closest degree. I have an answer; just don't understand if it is correct.
   In our inquiry we have two edges of this right triangle: the groundwork (46km) and the size (5.8km). To find the residual edge (the hypotenuse) we use Pythagoras and find that the hypotenuse is 46.36km.
   Now we use the sine direct to find the bend of fall, which is the bend between the hypotenuse and the base. We will call this bend "A". The sine direct is such that: a/sin(A) = b/sin(B), where the capitalized notes are the resisting twists to a specific edge of the triangle. So the edge resisting A is the size of 5.8km. We require another bend and resisting edge to entire the formula and the only edge which we now understand the edge extent and its resisting bend is the hypotenuse, as the resisting bend in right triangles to the hypotenuse is habitually 90 degrees. So b=46.34 and B=90, and a = 5.8
   we alternate this all into our sine rule:
   a/sin(A) = b/sin(B)
   5.8/sin(A) = 46.34/sin(90)
   5.8/sin(A) = 46.34/1
   5.8/46.34 = sin(A)
   A = inverse sine(5.8/46.34)
   = inverse sine(0.1251)
   = 7.186 degrees
   So our bend of fall is 7.186 degrees

   (The response for the bend of fall is correct presuming that the jet desires to land at the groundwork of the control tower. But contemplating that we are considering with soaring distances of kilometers, the expanse from the runway to the command tower is negligible.)

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2. Guest5575
   

   A pilot is flying an approach to land at an angle of three degrees. If the plane is 4 miles from touchdown, how high is the airplane? Furthermore, if the plane is flying in cloud and the pilot only sees the runway at a height of 400 feet, how far is the plane from touchdown?
   
   Answered either by Pythagoras, or the Sine Rule. Draw a right angled triangle with one angle 3 degrees, therefore other angle is 87. SinA/a = SinB/b. So Sin87/4 = Sin3/b
   
   b=height in miles. multiply by 6080 to get feet, if you want. Same procedure for latter part of question...

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