A common car battery consists of six identical galvanic cells, each of which carries out the following reaction:
Pb + PbO2 + 2 HSO4- + 2 H+ → 2 PbSO4 + 2 H2O
The value of E° for each of the cells is 2.04 V. Suppose that in starting a car on a cold morning a current of 108 A is drawn for 14 seconds from the car battery. How many grams of Pb would be consumed? (Mr(Pb)=207.19 g/mol)
I gets an answer: 3.2468 ; I really need someone help me check this, because i don't think i have done this right! Thanks a lot!
Tags: Battery, calculate, consumed, PB, weight